https://temml.org/docs/en/administration https://temml.org/docs/en/support_table https://temml.org/ TEMML A TeX-to-MathML conversion library in JavaScript. ---------------------------------------------------------------- h_{C}=\frac{y}{2} hC=y2 hC=y2 hC=y2[м] =============================================== h_{C}=\frac{0.2}{2}=0.1 [м] hC=0.22=0.1[м] hC=0.22=0.1[м] ================================= p_{a}=101325 Па pa=101325Па =========================== H=20 см H=20см ================= B=10 мм B=10мм ====================================== \rho = 1000 \frac{кг}{м^3} ρ=1000кгм3 ===================================== P P P ======================== \vec{P} P ====================== h_{C} hC ======================== h_{D_{coord}} hDcoord =========================== h_{D} hD ===================== h_{C}=\frac{H}{2} hC=H2 ==================== p=\rho gh_{C} p=ρghC ======================= w=B\cdot H w=BH ======================= P=p\cdot w P=pw ========================= I_{0}=\frac{B \cdot H^{3}}{12} I0=BH312 ================================================ h_{D}=h_{C}+\frac{I_{0}}{h_{C}\cdot w} hD=hC+I0hCw ==================================== h_{D_{coord}}=H - h_{C} hDcoord=HhC =================================== h_{C}=\frac{H}{2}, hC=H2, ============================= h_{C}=\frac{0.2}{2}=0.1 [м]. hC=0.22=0.1[м]. ===================== p_{c}=\rho gh_{C}, pc=ρghC, ============================ p_{c}=1000 \cdot 9.81 \cdot 0.1=490.5 [Па]. pc=10009.810.1=490.5[Па]. =============================== w=B\cdot H, w=BH, ===================================== w=0.1\cdot 0.2=0.02 [м^2]. w=0.10.2=0.02[м2]. ========================= P=p_{c}\cdot w, P=pcw, ============================ P=490.5\cdot 0.02=19.62 [Н]. P=490.50.02=19.62[Н]. ============================= I_{0}=\frac{B \cdot H^{3}}{12} I0=BH312 ======================== I_{0}=\frac{0.1 \cdot0.2^{3}}{12}=6.67^{-5} [м^4]. I0=0.10.2312=6.675[м4]. ============================= h_{D}=h_{C}+\frac{I_{0}}{h_{C}\cdot w}, hD=hC+I0hCw, ============================ h_{D}=0.1+\frac{6.667^{-5}}{0.1\cdot 0.02}=0.13 [м]. hD=0.1+6.66750.10.02=0.13[м]. ================================== h_{D_{coord}}=H-h_{D}, hDcoord=HhD, =================== h_{D_{coord}} = 0.2 - 0.13 = 0.07 [м]. hDcoord=0.20.13=0.07[м]. =================================